memincr_LE_inplace()

bool Chusov::Memory::memincr_LE_inplace ( void *  pData, std::size_t  cbData  )

noexcept

Increments an arbitrary precision integer specified by a vector of bytes in the Little-Endian order in place and returns the carry flag.

Parameters

[in,out]	pData	A pointer to a buffer which contains the integer to increment. On output, the buffer holds the result of the operation.
	cbData	Size of the integer in bytes.

Returns

A value of a carry flag which results from the operation.

The function considers the input vector to specify the integer in the Little-Endian byte order. That is, given that \(V_X = \{x_0, \dots, x_n\}\) is the input vector pointed to by pSrc, such that \(x_0\) is the first byte in memory of the vector, \(x_n\) is the last byte and n = cbData - 1, the input value for the operation is \(X = \sum_{i=0}^{n}x_i\cdot b^i\), where b = 2CHAR_BIT is a number of values that can be represented with one byte. To increment Big-Endian integers use memincr_BE_inplace.

To produce the result in a separate buffer leaving the original integer unchanged use memincr_LE_copy or memincr_LE.

See also

memincr_BE_inplace;
memincr_LE_copy;
memincr_LE;
memdecr_LE;
memadd_LE;
memsub_LE;
memmul_LE;
memdiv_LE.