◆ memcmp_BE()

int Chusov::Memory::memcmp_BE	(	const void *	pX,
		std::size_t	cbX,
		const void *	pY,
		std::size_t	cbY
	)

noexcept

Compares two arbitrary-precision integers specified with vectors of bytes in the Big-Endian order.

Parameters

[in]	pX	A pointer to a vector of `cbX` bytes representing the first integer.
	cbX	A byte size of the first integer.
[in]	pY	A pointer to a vector of `cbY` bytes representing the second integer.
	cbY	A byte size of the second integer.

Returns: A negative value, if the first integer is less then the second integer, a positive value if the first integer is greater than the second integer, otherwise the return value is zero.

Let b = 2^CHAR_BIT be a number of values that can be represented using one byte, n_x = cbX - 1, and n_y = cbY - 1. Assuming that pX points to the vector \(V_X = \{x_0,\dots,x_{n_x}\}\), where \(x_0\) is the first element of the vector \(V_X\), and pY points to the vector \(V_Y = \{y_0,\dots,y_{n_y}\}\), where \(y_0\) is the first element of the vector \(V_Y\), the function compares the corresponding Big-Endian integers \(X = \sum_{i=0}^{n_x}x_{n_x - i}\cdot b^i\) and \(Y = \sum_{i=0}^{n_y}y_{n_y - i}\cdot b^i\) and returns a negative value, if \(V_X < V_Y\); zero, if \(V_X = V_Y\), and a positive value, if \(V_X > V_Y\).

See also: memcmp_LE.